25y^2-52y+27=0

Solution for 25y^2-52y+27=0 equation:

Simplifying
25y2 + -52y + 27 = 0

Reorder the terms:
27 + -52y + 25y2 = 0

Solving
27 + -52y + 25y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(1 + -1y)(27 + -25y) = 0

Subproblem 1
Set the factor '(1 + -1y)' equal to zero and attempt to solve:

Simplifying
1 + -1y = 0

Solving
1 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1y = 0 + -1
-1y = 0 + -1

Combine like terms: 0 + -1 = -1
-1y = -1

Divide each side by '-1'.
y = 1

Simplifying
y = 1
Subproblem 2
Set the factor '(27 + -25y)' equal to zero and attempt to solve:

Simplifying
27 + -25y = 0

Solving
27 + -25y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-27' to each side of the equation.
27 + -27 + -25y = 0 + -27

Combine like terms: 27 + -27 = 0
0 + -25y = 0 + -27
-25y = 0 + -27

Combine like terms: 0 + -27 = -27
-25y = -27

Divide each side by '-25'.
y = 1.08

Simplifying
y = 1.08
Solution
y = {1, 1.08}